<PRE><B>Question 926873</B>
log(x+10)/x(x+4) = 0
(x+10)/x(x+4) = 1
x+10 = x(x+4)
x^2 +3x -10 = 0
(x+5)(x-2) = 0  (tossing out negative solution as extraneous)
x = 2
....
*[tex \large\ \ log_b(x) \ = \ y \ \ \Rightarrow\ \ b^y = x]
*[tex \large\ \ nlog_bx = log_b(x^n) ]
*[tex \large\ \ log_bx + log_by = log_b(xy) ]
*[tex \large\ \ log_bx - log_by = log_b(x/y) ] ******
*[tex \large\ \ log_b1 = 0] ******
*[tex \large\ \ log_bb = 1]
</PRE>