Question 926839
 ax^2+bx+c=0
one root is 2+√3 
Then... the other root is 2-√3 
x - (2+√3 ))(x - (2-√3)) = 0
x^2 - (4+1) = 0
x^2 -4x + 7  = 0
{{{x = (-b +- sqrt( b^2-4*a*c ))/(2*a) }}}
{{{x = (4+- sqrt( 12 ))/(2) }}}
{{{x = (4+- sqrt( 4*3 ))/(2) }}}
{{{x = (4+- 2sqrt(3 ))/(2) }}}
{{{x = (2+- sqrt(3 ))}}}