Question 926841
f(x) = -3x(x+2)^2 (x-4)^3 
for x > 4, (x-4)^3 > 0  and  therefore, end behavior for f(x) = -inf, due to the negative Leading Coefficient
{{{drawing(300,300,   -10,10,-1000,1000,  
 grid(1),
circle(4, 0,0.4),
circle(-2,0,0.4),
graph( 300, 300, -10,10,-1000,1000,0, (-3x)((x+2)^2)(x-4)^3 ))}}}