Question 926810

we are given
{{{sin(A) + cos(A) = sqrt(2)}}} => {{{A=45}}}

substitute {{{45}}} degrees for {{{A}}}


{{{sin(45)+cos(45) = sqrt(2)}}}


{{{1/sqrt(2)+1/sqrt(2)=sqrt(2)}}}


{{{2/sqrt(2)=sqrt(2)}}}


{{{2sqrt(2)/(sqrt(2)sqrt(2))=sqrt(2)}}}


{{{2sqrt(2)/(sqrt(2))^2=sqrt(2)}}}


{{{cross(2)sqrt(2)/cross(2)=sqrt(2)}}}


{{{sqrt(2)=sqrt(2)}}}