Question 78424
(1/x)-(1/3)=(6/x^2)
The lcm is 3x^2.
Multiply thru by 3x^2 to get:
3x-x^2=18
x^2-3x+18=0
(x-6)(x+3)=0
x=6 or x=-3
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Checking these answers:
If x=6: 1/6-2/6=6/36------false
If x=-3: -1/3-1/3=6/9-----false
Therefore No Solution.
===========Cheers,
Stan H.