Question 926737
{{{log(a,x)}}} can be converted to the base {{{b}}} by the formula  {{{log(b,x) /log(b,a)}}} 


{{{log ( a, b^2)*log( b, a^3)=6}}}...use the formula  {{{log(b,x) /log(b,a)}}} 


{{{(log ( b, b^2)/log( b,  a))*log( b,  a^3)=6}}}

{{{(2log ( b, b)/cross(log( b,  a)))*3cross(log( b,  a))=6}}}

{{{2(log ( b, b))*3=6}}}..........{{{log ( b, b)=1}}}

{{{2*3=6}}}

{{{6=6}}}