Question 926736

if you mean

{{{log(a, b^2)*log(b, a^3)=6}}} then

{{{log(a, b^2)*log(b, a^3)=6}}}

{{{(log(b^2)/log(a))*(log( a^3)/log(b))=6}}}

{{{(2log(b)*3log( a))/(log(a)log(b))=6}}}

{{{(6log(b)*log(a))/(log(a)log(b))=6}}}

{{{(6cross(log(b))*cross(log(a)))/(cross(log(a))cross(log(b)))=6}}}

{{{6=6}}}....proof that {{{log(a, b^2)*log(b, a^3)=6}}}