Question 926679
Assuming the first term is a_1, the expression *[tex \large a_n = 12 \times (0.5)^{n-1}] represents the sequence since a_1 = 12*(0.5)^0 = 12, and it decreases by a factor of 2. You just have to try a couple things and check that it works.


The recursive formula is *[tex \large a_1 = 12] and *[tex \large a_n = \frac{1}{2} a_{n-1}] for *[tex \large n \ge 2].