Question 926657
Let g(x) = x√(64x^2+25) and h(t)=5/8 cot(t) for 0 Find g(h(t)), simplify and write the answer in terms of sin(t) and cos(t)
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g(h(t)) = g((5/8)cot(t))
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= sqrt[(64[5/8cot(t)]^2+25]
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= sqrt[64*(25/64cot^2(t)+25]
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= sqrt[[25(cot^2(t)+1)]
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= sqrt[25csc^2(t)]
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= 5csc(t)
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= 5/sin(t)
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Cheers,
Stan H.
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