Question 926360

{{{f(x)=x-3}}} 
{{{g(x)=8x^2}}}

 {{{(f-g)(x)= f(x)-g(x)}}}, so we have

{{{(f-g)(x)= x-3-8x^2}}}

{{{(f-g)(x)= -8x^2+x-3}}}