Question 926337
Given {{{f(x) = ln (x)}}} evaluate 

{{{f(e^(ln(3)))=ln(e^(ln(3)))}}}  ....{{{ln(3)=1.098612288668}}}


{{{f(e^(ln(3)))=ln(e^(1.098612288668))}}}

{{{f(e^(ln(3)))=ln(e^3)}}} .............{{{y=ln(x)}}}, exponential form is {{{x=e^y}}}

so, {{{e^3=e^y}}} => {{{y=3}}} and

{{{f(e^(ln(3)))=3}}}



{{{f(e^(2ln(3)))=ln(e^(2ln(3)))}}}

{{{f(e^(2ln(3)))=ln(e^(ln(3^2)))}}} 

{{{f(e^(2ln(3)))=ln(e^(ln(9)))}}} 

{{{f(e^(2ln(3)))=ln(e^9)}}}...use same procedure as above:

{{{e^9=e^y}}} => {{{y=9}}}

{{{f(e^(2ln(3)))=9}}}