Question 926340

given {{{f(x) = ln (x)}}}, evaluate

{{{f(e^-5)}}}

 {{{f(e^-5) = ln (e^-5)}}}

 {{{f(e^-5) = ln (1/e^5)}}}

 {{{f(e^-5) = ln (1)-ln(e^5)}}}

{{{f(e^-5) = ln (1)-5ln(e)}}}

{{{f(e^-5) = ln (1)-5ln(e)}}}... {{{ln (1)=0}}} and {{{ln (e)=1}}}

{{{f(e^-5) = 0-5*1}}}

{{{f(e^-5) = -5}}}