Question 926299
A rock is thrown upward with a velocity of 13 meters per second from the top of a 39 meter high cliff, and it misses the cliff on the way back down. When will the rock be 11 meters from the water below? Round answer to two decimal places.
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You should give the function to use.
For metric on Earth, h(t) = -4.9t^2 + vt + h0 is commonly used, but sometime it's -5t^2.
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h(t) = -4.9t^2 + vt + h0
For this problem:
h(t) = -4.9t^2 + 13t + 39
h(t) = -4.9t^2 + 13t + 39 = 11
It's a quadratic, solve for t, ignore the negative solution.