Question 78386
a^2(b-c)-16b^2(b-c)
Here (b-c) is common to both the terms
==> (b-c)(a^2 - 16b^2)
==>  (b-c)[(a)^2 - (4b)^2]

==>  (b-c)(a+4b)(a-4b) [as a^2 - b^2 = (a+b)(a-b)]

Thus the factorized form is (b-c)(a+4b)(a-4b)