Question 926188
Use a variable.
{{{5^x=19}}}.


{{{log(10,(5^x))=log(10,19)}}}
{{{x*log(10,5)=log(10,19)}}}
{{{x=log(10,19)/log(10,5)}}}
{{{highlight(x=1.2788/0.6990)}}}


That was not according to the instructions you listed.  Your instructions would be like,
{{{log(5,19)=x}}} and then use the change of base formula.






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CHANGE OF BASE FORMULA
Convert logarithm in base b into logarithm in base c
{{{log(b,p)=log(c,p)/log(c,b)}}}