Question 926149


{{{f(x)=x^3+(12-4i)x^2+(32-48i)x-128i}}},  given: {{{ k=4i}}}

{{{f(x)=x^3+12x^2-4i*x^2+32x-48i*x-128i}}} .....rearrange

{{{f(x)=x^3+12x^2+32x-4i*x^2-48i*x-128i}}}....group

{{{f(x)=(x^3+12x^2+32x)-(4i*x^2+48i*x+128i)}}}

{{{f(x)=x(x^2+12x+32)-4i(x^2+12x+32)}}}

{{{f(x)=(x-4i)(x^2+12x+32) }}}

 {{{f(x)=(x-4i)(x^2+8x+4x+32)}}} 

{{{f(x)=(x-4i)(x+4)(x+8) }}}..in completely factored form