Question 926082

please help me ...........
if x is positive integer and (x-6)^2=9,then x^2
<pre>
{{{(x - 6)^2 = 9}}}
{{{x - 6 = 0 +- sqrt(9)}}} ------ Taking square root of both sides
{{{x - 6 = 0 +- 3}}}
{{{x = 6 +- 3}}}
x = 9 or 3
{{{x^2 = 9^2}}}, or {{{x^2 = 3^2}}}______{{{highlight_green(x^2 = system (81_or, 9))}}}