Question 926089


solve for x; you mean solve for {{{p}}}


{{{log(3, 81)=p+6}}}...in base {{{10}}} will be

{{{log(81)/log(3)=p+6}}}

{{{log(81)=(p+6)log(3)}}}

{{{log(3^4)=log(3^(p+6))}}}...since log same, we have

{{{3^4=3^(p+6)}}}...since bases same,exponents must be same too

{{{4=p+6}}}...solve for {{{p}}}

{{{4-6=p}}}

{{{-2=p}}}