<PRE><B>Question 925958</B>
What is radical x minus 3 (outside of the radical) divided by radical x plus 3 (outside of the radical?
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[sqrt(x)-3] / [sqrt(x)+3] 
Multiply numerator and denominator by (sqrt(x)-3) to get::
= [sqrt(x)-3]^2/(x-9)
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= [x - 6sqrt(x) + 9] / (x-9)
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= [x+9 - 6sqrt(x)]/(x-9)
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Cheers,
Stan H.
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