Question 925845
log(x+4)=log(5x-5)
{{{log(x+4)-log(5x-5)=0}}}
{{{log(((x+4)/(5x-5)))=0}}}
change to exponential form: base(10) raised to log of the number(0)=number(x+4)/(5x-5)
10^0=(x+4)/(5x-5)
(x+4)/(5x-5)=1
x+4=5x-5
4x=9
x=9/4