Question 78278
I'm just adding onto the previous poster's work...
Note: when you take a square root you get 


{{{ x -3 =0+- sqrt (12)}}} (plus or minus the square root of 12)


{{{ x =0+- sqrt (12)+3}}} Add 3 to both sides

So you should have 2 answers:


{{{ x =sqrt (12)+3}}} or {{{ x =-sqrt (12)+3}}}

Which reduce to 

{{{ x =2*sqrt (3)+3}}} or {{{ x =-2*sqrt (3)+3}}}