Question 78303
Since the denominator cannot equal zero, we must look for values that make this true

{{{(4x-5)(x+1)=0}}}

Set each factor equal to zero

{{{4x+5=0}}}

{{{4x=-5}}} Subtract 5 from both sides

{{{x=-5/4}}} Divide both sides by 4

Set x+1 equal to zero

{{{x+1=0}}}

{{{x=-1}}} Subtract 1 from both sides

So x cannot equal -1 or -5/4, this means we must exclude these numbers from our domain.