Question 925667
A parabola has its focus at (7, -4) and directrix y = 2 
(directrix an horizontal line...Parabola Opening Downward) x = 7 the line of Symmetry
the vertex form of a Parabola opening up(a>0) or down(a<0), {{{y=a(x-h)^2 +k}}}
where(h,k) is the vertex  and  x = h  is the Line of Symmetry , With Directrix y = (k - p)where a = 1/4p

Distance from  - 4 t 2 = 6, 6/2 = 3, p = -3, V(7,-1), a =  1/4p = -1/12
.......
{{{y= (-1/12)(x-7)^2 -1}}}

{{{drawing(300,300,   -10,18,-10,10,  blue(line(7,10,7,-10))  ,  
 grid(1),
circle(7, -1,0.4),
circle(7,-4,0.4),
graph( 300, 300, -10,18,-10,10,0,2, -(1/12)(x-7)^2 -1))}}}