Question 925594
rule out C and E  and A for sure(we can determine ME not SE) 
90% confidence interval is found to be : (-0.2, 5.4).  
ME = (5.4-(-.2))/2 = 2.8  
{{{(5.4 - 2.8) = 2.6}}}
90%CI: is 2.6 ± 2.8
..........
90% confidence interval is found to be:  2.6 ± 2.8
...
unknown population standard deviations... 
the critical value used to determine CI would have been as a <u>t-score</u> rather than a z score
two-sided: t-value with a  cumulative probability equal to 0.95
......
90% confidence interval <u>is found to be</u>:  2.6 ± 2.8   (rules out B)