Question 925565
{{{h=6+2b}}}
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{{{A=(1/2)bh=8}}}
{{{bh=16}}}
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Substituting,
{{{b(6+2b)=16}}}
{{{2b^2+6b=16}}}
{{{b^2+3b=8}}}
{{{b^2+3b+9/4=8+9/4}}}
{{{(b+3/2)^2=41/4}}}
{{{b+3/2=0 +- sqrt(41)/2}}}
{{{b=-3/2 +- sqrt(41)/2}}}
Only the positive solution makes sense here.
{{{b=(sqrt(41)-3)/2}}}
{{{h=6+sqrt(41)-3}}}
{{{h=3+sqrt(41)}}}