<PRE><B>Question 925538</B>
A researcher wants to study the mean amount of time (in minutes) that kindergartners spend watching TV each day. 
Find the sample size necessary to estimate the mean with a 10-min margin of error. Assume that a 90% confidence 
level is desired and that a pilot study showed that the standard deviation is estimated to be 44min
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n = [z*s/E]^2
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n = [1.645*44/10]^2 = 53 when rounded up
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Cheers,
Stan H.
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