Question 925529
x = outbound speed
y = inbound speed
x = y + 25 kph
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s = d/t
d = st
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outbound:
x = d/4
d = 4x
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inbound:
y = d/6
d = 6y
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4x = 6y
4(y + 25) = 6y
4y + 100 = 6y
2y = 100
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answer:
y = inbound speed = 50 kph
x = outbound speed = 75 kph
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