Question 925425
through ({{{8}}},{{{ -1}}}) and perpendicular to {{{8y=x-16}}}

{{{8y=x-16}}}

{{{y=x/8-16/8}}}

{{{y=(1/8)x-2}}}


*[invoke equation_parallel_or_perpendicular "perpendicular", "1/8", -2, 8, -1]