Question 925380
the standard slope-intercept form for an equation of a line is 
{{{y = highlight_green(m)x + highlight(b)}}}  where m is the slope and b the y-intercept.  
perpendicular to 8y=x-16 0r {{{y = highlight_green(1/8)x + highlight(-2)}}} , 
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New Line
Through (3, -8) 
m = -8  (negative reciprocal of (1/8) {{{-8(1/8) = -1}}}
***Using point-slope form, {{{y - y[1] = m(x - x[1])}}}
y + 8 = -8(x-3)
y = -8x - 16
0r
8x + y = -16