Question 925339
{{{lim( x->0, (log(x)/x))}}}
Using:  l'Hopital's rule

f(x) = log (x)
f' = 1/x
...
g(x) = x
g' = 1
...f'/g' = (1/x)/1 = 1/x
{{{lim( x->0, (1/x)) = infinity}}}