<PRE><B>Question 925258</B>
A ball with a 22-in. circumference is tightly packed into a cubical box for shipment. (Round your answers to the nearest whole number.)
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Find the diameter of the ball::
pi*d = 22
diameter = 22/pi inches
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 (a) What is the volume of the ball in cubic inches?
V = (4/3)pi*r^3 = (4/3)pi*(11/pi)^3 = (1774.67)/pi^2 in^3
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(b) What is the smallest possible volume for the box? in3
V = s^3 = (22/pi)^3 = 10648/pi^3 in^3
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(c) What percent of the space in the box is occupied by the ball?
 [(4/3)pi*(11/pi)^3 / (22/pi)^3 = [(4/3)*11^3/p^2]/(22/pi)^3)
= [(4/3)*11^3*pi/22^3] = 52.36%
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Cheers,
Stan H.
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