Question 925215
{{{X/Y=4/3}}}
{{{X=(4/3)Y}}}
{{{X^2=(16/9)Y^2}}}
Substituting,
{{{(16/9)Y^2+Y^2=40^2}}}
{{{(25/9)Y^2=1600}}}
{{{Y^2=576}}}
{{{Y=24}}}
Then,
{{{X=(4/3)24}}}
{{{X=32}}}