Question 925208
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There are two ways to do it.  Without algebra and with algebra.

First way: without algebra:
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In a two-digit number, the digit in the tens place is three times the digit in the one place. 
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That narrows it down to 31, 62, or 93
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The sum of the digit is four more than the difference of the digit.
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The sum and difference of the digits of 31 are 2 and 4. That's not it because
4 isn't 4 more than 2.
The sum and difference of the digits of 62 are 4 and 8. That's it because
8 is 4 more than 2. 

So the answer is 62.

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Second way: with algebra:
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In a two-digit number, the digit in the tens place is three times the digit in the one place. 
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   t = 3u

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The sum of the digit is four more than the difference of the digit.
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 t+u = t-u+4

Subtract t from both sides

   u = -u+4
  
Add u to both sides

  2u = 4

Divide both sides by 2

   u = 2

Substitute in 

   t = 3u
   t = 3(2)
   t = 6
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What is the number?
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The number is 62.

Edwin</pre>