Question 925118
Slope of line perpendicular to {{{2x+5y-3=0}}} would be {{{m=5/2}}};


y-intercept of {{{2x+3y+6=0}}}
{{{3y=-2x-6}}}
{{{y=-2x/3-6/3}}}
{{{y=-2x/3-2}}}
The point (0,-2);


The line asked is {{{highlight(y=(5/2)x-2)}}}, perpendicular to first given equation, same y-intercept as the second given equation.