Question 924978
p(error) = .12,  n = 52
Using a TI calculator 0r similarly a Casio fx-115 ES plus
P( x > 6) = 1 - binomcdf(52, .12, 6) -= 1 - .5655 = .4345
P(x ≤ 6) = binomcdf( 52, .12, 6) = .5655
P(x = 6) = binompdf(52, .12, 6) = .1698 
0r
P(x = 6) = 52C6(.12)^6(.88)^46