Question 924807

let integer be {{{x}}}
the least positive integer with a squre root greater than {{{8}}}:

{{{sqrt(x)>8}}}...square both sides

{{{(sqrt(x))^2>8^2}}}

{{{x>64}}}

the least positive integer greater than {{{64}}} is {{{65}}}

{{{sqrt(65)>8}}}

{{{8.06225774829855>8}}}