Question 924734
x = speed of bus a
y = speed of bus b
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combined speed of buses = x + y
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x = y + 10
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s = d/t
x + y = 532/2
x + y = 266
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put the system of linear equations into standard form
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x = y + 10
x + y = 266
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x - y = 10
x + y = 266
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solution:
x = speed of bus a = 138 kph
y = speed of bus b = 128 kph
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