Question 924531
to sketch a graph for the line {{{y=(7/2)x-2}}} all you need is to find two points that lie on a line (easiest is to find x an y-intercepts)

so, set {{{x=0}}} and find {{{y-intercept}}}

{{{y=(7/2)0-2}}}

{{{y=-2}}}

{{{y-intercept}}} is at the point ({{{0}}},{{{-2}}})

set {{{y=0}}} and find {{{x-intercept}}}

{{{0=(7/2)x-2}}}

{{{0+2=7x/2}}}

{{{2*2=7x}}}

{{{4=7x}}}

{{{4/7=x}}}

{{{x-intercept}}} is at the point ({{{4/7}}},{{{0}}})

plot these points and draw a line through:

{{{drawing( 600,600, -5, 10, -10, 10,circle(4/7,0,.15),circle(0,-2,.15), graph( 600,600, -5, 10, -10, 10, (7/2)x-2)) }}}