Question 924528
{{{x/3 + y/6=1}}}.....(1).....both sides multiply by {{{6}}}

{{{x/2 - y/4=1}}}.....(2).....both sides multiply by {{{4}}}
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{{{(x/3)6 + (y/6)6=1*6}}}.....(1)
{{{(x/2)4 - (y/4)4=1*4}}}.....(2)
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{{{2x + y=6}}}.....(1)
{{{2x - y=4}}}.....(2)
___________________....add both (1) and (2)

{{{2x+cross(y)+2x-cross(y) =6+4}}}

{{{4x =10}}}

{{{x =10/4}}}

{{{x =5/2}}}

{{{highlight(x =2.5)}}}



then go to {{{2x + y=6}}}.....(1) and find {{{y}}}

{{{2*(2.5) + y=6}}}.....(1)

{{{5+ y=6}}}

{{{y=6-5}}}

{{{highlight(y=1)}}}


check:
would be better and more accurate if we use {{{x =5/2}}} instead of {{{x =2.5}}}


{{{x/3 + y/6=1}}}.....(1)

{{{2.5/3 + 1/6=1}}}

{{{5/6 + 1/6=1}}}

{{{6/6=1}}}

{{{1=1}}}


{{{(x/2) - (y/4)=1}}}.....(2)

{{{((5/2)/2) - (1/4)=1}}}

{{{5/4 - (1/4)=1}}}

{{{4/4)=1}}}

{{{1=1}}}


{{{ graph( 600, 600, -10, 10, -10, 10, 2x-4, -2x+6) }}}