Question 924412

For 5 bulbs,
{{{P=1(0.96)^5*(0.04)^0+
5(0.96)^4*(0.04)^1+
10(0.96)^3*(0.04)^2+
10(0.96)^2*(0.04)^3+
5(0.96)^1*(0.04)^4+
1(0.96)^0*(0.04)^5}}}
.
.
.
For two defectives,
{{{P=10(0.96)^3*(0.04)^2=0.014}}}