Question 78177
sqrt{{{4x+1}}}+3=0
sqrt{{{4x+1}}}=-3
{sqrt{{{4x+1}}}^2=(-3)^2
4x+1=9
4x=8
x=2
check
sqrt{{{4(2)+1}}}+3=0
sqrt{{{9}}}+3=0
6=0
Answer does not check out.
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Cheers,
Stan H.