Question 78177
{{{sqrt(4x+1)+3=0}}} Start with the given expression
{{{sqrt(4x+1)=-3}}} Subtract 3 from both sides 
Since this equation is never true, there are no solutions  (you cannot take a square root and get a negative number). But for the sake of the problem lets see what happens...


{{{(sqrt(4x+1))^2=(-3)^2}}} Square both sides. Both sides will be positive so we will have 1 answer
{{{4x+1=9}}} 
{{{4x=8}}} Subtract 1 from both sides
{{{x=2}}} Divide both sides by 4



Check:
{{{sqrt(4x+1)+3=0}}}
{{{sqrt(4(2)+1)+3=0}}} Plug in x=2
{{{sqrt(8+1)+3=0}}}
{{{sqrt(9)+3=0}}}
{{{3+3=0}}}
{{{6=0}}} This is not true. We should have {{{-3+3=0}}}. But since we cannot take a square root and get a negative number, we have no solution.