Question 924420
A man is 24 years older than his son. Three years ago he was eight years less than twice his son's age three years from now. How old is the man?
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Equations:
f = s + 24
f-3 = 2(s+3)-8
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Substitute for "f" and solve for "s"::
s+24-3 = 2s - 2
s+21 = 2s-2
s = 23 yrs (son's age now)
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f = s + 24 = 47 yrs (father's age now)
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Cheers,
Stan H.
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