Question 924396
Treat them like any other number.
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x-intercept : Set {{{y=0}}}, solve for {{{x}}}.
{{{x+(4/3)(0)=8}}}
{{{x=8}}}
(8,0)
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y-intercept : Set {{{x=0}}}, solve for {{{y}}}.
{{{0+(4/3)y=8}}}
{{{4y=24}}}
{{{y=6}}}
(0,6)