Question 924271
Take the square root of both sides and simplify. Don't forget the plus/minus.



*[Tex \Large (x+1)^2= -8]



*[Tex \Large x+1= \pm\sqrt{-8}]



*[Tex \Large x+1= \pm\sqrt{-1*4*2}]



*[Tex \Large x+1= \pm\sqrt{-1}*\sqrt{4}*\sqrt{2}]



*[Tex \Large x+1= \pm i*2*\sqrt{2}]



*[Tex \Large x+1= \pm 2i\sqrt{2}]



*[Tex \Large x= -1\pm 2i\sqrt{2}]



*[Tex \Large x= -1 + 2i\sqrt{2} \ \ \ or \ \ \ x = -1 - 2i\sqrt{2}]



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The two solutions are 


*[Tex \Large x= -1 + 2i\sqrt{2} \ \ \ or \ \ \ x = -1 - 2i\sqrt{2}]


you can condense them into this shorthand "plus/minus" notation


*[Tex \Large x= -1\pm 2i\sqrt{2}]

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Let me know if that helps or not. Thanks.


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