Question 924155
x = speed of airplane
y = speed of train
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s = d/t
t = d/s
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airplane time:
t = 385/x
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train time:
t = 110/y
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t = 385/x = t = 110/y
385/x = 110/y
385y = 110x
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x = 4y - 30
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385y = 110x
x = 4y - 30
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put the system of linear equations into standard form
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110x - 385y = 0
x - 4y = -30
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solution:
x = speed of airplane = 210 kph
y = speed of train = 60 kph
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