Question 924104
16*A^2*64=(4*B)^2
16*(A^2)*64=16*B^2  Divide both sides by 16
64*A^2=B^2   Take the square root of both sides
8A=B 

The problem asks to determine how many times greater B is than A.
If it takes 8 A's to make 1 B, the B must be 8 times greater than A

Hope this helps--ptaylor