Question 923988
There is a typo.
Your formula does not make sense.
With {{{h-3/2}}} , at {{{h=0}}} (administration time), and {{{h=1}}} hour,
you would have, respectively,
{{{0-3/2=-3/2}}} and {{{1-3/2=-1/2}}} as a result.
Those are negative numbers, and that does not make sense.
What's worse, at {{{h=2}}} hours, and at {{{h=3}}} hours ,
the formula would tell you that the amount in the bloodstream would be
{{{2-6/2=1/2}}} and {{{3-2/2=3/2}}} respectively.
It makes absolutely no sense to have negative levels in the blood at first, and then have the levels increase {linearly no less) with time. 


The fraction of the original dose of contrast material remaining in the patient's bloodstream h hours after it is injected
must be something such as {{{e^(-"3/2"h)}}}, or {{{2^(-"3/2"h)}}} .
In general, that fraction of the initial dose should be {{{B^(-K*h)}}} with some positive constants {{{B}}} and {{{K}}} .
It has to be that what remains is a fraction of what was administered,
starting as 1 (the whole amount administered) at {{{h=0}}} hours after administration,
and decreasing exponentially with time.
You need the right formula to know what fraction (something like 1/5 or 20%) remains in the bloodstream.
If they want an amount in milligram of drug, you also need the dose administered.