Question 924066
{{{y= abs(x)-4}}}

remember, {{{abs(x)}}}  means only how far a number is from zero,  {{{abs(3)=3}}} and also {{{abs(-3)=3}}}

the table

{{{x}}}|{{{y}}} ....=>{{{y= abs(x)-4}}} plug in {{{x}}}

{{{-3}}}|{{{-1}}} ....=>{{{y= abs(-3)-4=3-4=-1}}} 

{{{-1}}}|{{{-3}}} ....=>{{{y= abs(-1)-4=1-4=-3}}}

{{{0}}}|{{{-4}}} ....=>{{{y= abs(0)-4=0-4=-4}}}

{{{1}}}|{{{-3}}} ....=>{{{y= abs(1)-4=1-4=-3}}}

{{{2}}}|{{{-2}}} ....=>{{{y= abs(2)-4=2-4=-2}}}

{{{3}}}|{{{-1}}} ....=>{{{y= abs(3)-4=3-4=-1}}} 


now plot points on a graph:


{{{drawing( 600, 600, -10, 10, -10, 10,grid(1),circle(2,-2,.12),locate(2,-2,p(2,-2)),circle(3,-1,.12),locate(3,-1,p(3,-1)),circle(1,-3,.12),locate(1,-3,p(1,-3)),circle(0,-4,.12),locate(0,-4,p(0,-4)),circle(-1,-3,.12),locate(-1,-3,p(-1,-3)),circle(-3,-1,.12),locate(-3,-1,p(-3,-1)), graph( 600, 600, -10, 10, -10, 10, 0))}}} 
  

now draw a line through these points:


{{{drawing( 600, 600, -10, 10, -10, 10,grid(1),circle(2,-2,.12),locate(2,-2,p(2,-2)),circle(3,-1,.12),locate(3,-1,p(3,-1)),circle(1,-3,.12),locate(1,-3,p(1,-3)),circle(0,-4,.12),locate(0,-4,p(0,-4)),circle(-1,-3,.12),locate(-1,-3,p(-1,-3)),circle(-3,-1,.12),locate(-3,-1,p(-3,-1)), graph( 600, 600, -10, 10, -10, 10, abs(x)-4))}}}