Question 924030
box containing 10 balls:  6B , 4G, 
3 balls drawn, each ball being replaced in the box before the next draw is made
a) P(3 same color) = P(3B) + P(3G) = {{{( 6C3)/(10C3) + ( 4C3)/(10C3)= (20 + 4)/120 }}} = .2
b) P(each color is represented) = 1 - P(3 same color) = .8